Thetagamand
6 год назад
Вычислить
sin(67)*sin(53)-cos(67)*sin(37)
ОТВЕТЫ
Saneschyu
Jun 30, 2019
Sin53=sin(90-37)=cos37
sin67*cos37-cos67*sin37=sin(67-37)=sin30=1/2
sin67*cos37-cos67*sin37=sin(67-37)=sin30=1/2
Sin67°sin53°-cos67°sin37°=
sin67°sin53°-cos67°sin(90°-53°)=
sin67°sin53°-cos67°cos53°=
-(cos(67°+53°))=-cos120°=
1/2.
sin67°sin53°-cos67°sin(90°-53°)=
sin67°sin53°-cos67°cos53°=
-(cos(67°+53°))=-cos120°=
1/2.
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