53^2x-1 -9^x-0.5+3^2x+49^x-1 = 25

Question

Математика

Нифонт

6 год назад

53^2x-1 -9^x-0.5+3^2x+49^x-1 = 25

ОТВЕТЫ

Олимпий

Jul 7, 2019

$5*3^{2x-1} - 3^{2x-1} + 3^{2x} +4*3 ^{2x-2} =25amp;#10; amp;#10;5*3^{2x}/3-3^{2x}/3+3^{2x} +4*3^{2x}/9=25 \\ amp;#10; 3^{2x}(5/3-1/3+1+4/9)=25 \\ amp;#10;3^{2x}(15/9-3/9+9/9+4/9)=25amp;#10; \\ 3^{2x}*25/9=25 \\ amp;#10;3^{2x}=9 \\ amp;#10;3^{2x}=3^2 \\ amp;#10;2x=2 \\ amp;#10;x=1$

89

5*3^2x-1 -9^x-0.5+3^2x+4*9^x-1 = 25

53^2x-1 -9^x-0.5+3^2x+49^x-1 = 25