Coirin
6 год назад
Помогите пожалуйста!
ОТВЕТЫ
Zaabnakly
Jul 7, 2019
{x+y=π/2
{sinx+cosx=√2; √2sin(π/4+x)=√2; sin(π/4+x)=1; π/4+x=π/2; x=(2π-π)/4;
x=π/4; y=π/2-π/4; y=π/4 (π/4;π/4)
{sinx+cosx=√2; √2sin(π/4+x)=√2; sin(π/4+x)=1; π/4+x=π/2; x=(2π-π)/4;
x=π/4; y=π/2-π/4; y=π/4 (π/4;π/4)
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