
Дубровин
7 год назад
Sinx/2+cosx = 1 срочно
ОТВЕТЫ

Vagapibba
Jul 5, 2019
1-cosx=2*sin(x\2)
2sin²(x/2)-2sin(x/2)=0
sin(x/2)(sin(x/2)-1)=0
a) sin(x/2)=0
x/2=πn
x1=2πn
б)
sin(x/2)-1=0
sin(x/2)=1
x/2=π/2+2πn
x2=πn+4πn
2sin²(x/2)-2sin(x/2)=0
sin(x/2)(sin(x/2)-1)=0
a) sin(x/2)=0
x/2=πn
x1=2πn
б)
sin(x/2)-1=0
sin(x/2)=1
x/2=π/2+2πn
x2=πn+4πn
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