Решите уравнение:
А)sin x = -0,5√2
Б)2cos2x-1 = 0
В)2sin(x/2-П/6) = -1

1/   sinx=-√2/2   x=(-1)ⁿ(-π/4)+πn   n∈Z
2/   cos2x=1/2  2x=+-π/3+2πn    x=+-π/6+πn   n∈Z
3/   sin(x/2-π/6)=-1/2   x/2=(-1)ⁿ(-π/6)+πn+π/6
x=(-1)ⁿ(-π/3)+2πn+π/3    n∈Z