Софья
5 год назад
Вычислить 2log²₂3-log²₂12-log₂3*log₂12 / 2log₂3+log₂12
ОТВЕТЫ
Прокофьевич
Jun 30, 2019
(2log(2)^2 3-2log(2)3*log(2)12+log(2)3*log(2)12-log(2)^2 12)/2log(2)3+log(2)12=
(2log(2)3*(log(2)3-log(2)12)+log(2)12*(log(2)3-log(2)12))/(2log(2)3+log(2)12)=
((log(2)3-log(2)12)(2log(2)3+log(2)12))/(2log(2)3+log(2)12)=
log(2)3-log(2)12= log(2)3/12= log(2) 1/4=
log(2) 2^-2= -2
(2log(2)3*(log(2)3-log(2)12)+log(2)12*(log(2)3-log(2)12))/(2log(2)3+log(2)12)=
((log(2)3-log(2)12)(2log(2)3+log(2)12))/(2log(2)3+log(2)12)=
log(2)3-log(2)12= log(2)3/12= log(2) 1/4=
log(2) 2^-2= -2
12
