Андреевич
6 год назад
Пусть y = f(x) - периодическая функция с периодом 3,
определённая для всех действительных значений х, причём f(3) = 7, f(1) = 3, f(3,5) = 11, f(0,1) = 0, f(17) = 13, f(5) = 10.
f(-134,5) =
f(-8.9) =
f(0) =
f(-76) =
f(20) =
f(70)
ОТВЕТЫ
Пармен
Jun 30, 2019
F(-134,5) = f(-134,5 + 46*3) = f(3,5) = 11
f(-8,9) = f(-8,9 + 3*3) = f(0,1) = 0\
f(0) = f(3) = 7
f(-76) = f(-76 + 3*31) = f(17) = 13
f(20) = f(20-3) = f(17) = 13
f(70) = f(70 - 23*3) = f(1) = 3
f(-8,9) = f(-8,9 + 3*3) = f(0,1) = 0\
f(0) = f(3) = 7
f(-76) = f(-76 + 3*31) = f(17) = 13
f(20) = f(20-3) = f(17) = 13
f(70) = f(70 - 23*3) = f(1) = 3
F(-134,5) = f(-46*3-3,5) = f(3,5) = 11
f(-8,9) = f(-3*3 + 0,1) = f(0,1) = 0
f(0) = f(0*3 + 3) = f(3) = 7
f(-76) = f(-31*3 + 17) = f(17) = 13
f(20) = f(5*3 + 5) = f(5) = 10
f(70) = f(23*3 +1) = f(1) = 3
f(-8,9) = f(-3*3 + 0,1) = f(0,1) = 0
f(0) = f(0*3 + 3) = f(3) = 7
f(-76) = f(-31*3 + 17) = f(17) = 13
f(20) = f(5*3 + 5) = f(5) = 10
f(70) = f(23*3 +1) = f(1) = 3
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