Напишіть будь ласка 9,10,11

Question

Математика

Boesam

7 год назад

Напишіть будь ласка 9,10,11

ОТВЕТЫ

Фома

Jun 30, 2019

$5^{2x+5} - 2^{2x+10} + 3*5^{2x+2} - 2^{2x+3} = 0|:2^{2x+2}\\amp;#10;125*( \frac{5}{2} )^{2x+2}-2^8+3* (\frac{5}{2} )^{2x+2} - 2 = 0\\amp;#10;( \frac{5}{2} )^{2x+2} = t\\amp;#10;125t - 256 +3t-2=0\\amp;#10;128t=258\\amp;#10;t= \frac{129}{64}\\amp;#10; ( \frac{5}{2} )^{2x+2} = \frac{129}{64} \\amp;#10; ( \frac{5}{2} )^{2x} = \frac{129}{400} \\amp;#10; ( \frac{5}{2} )^{x} = \frac{ \sqrt{129}}{20} \\amp;#10;x = log_{2,5}\frac{ \sqrt{129}}{20}$

10
$2^{2x-1}+2^{2x-2}+2^{2x+2}=2^{2x-3} + 78\\amp;#10;2^{2x-3}(2^2+2+2^5-1)=78\\amp;#10;2^{2x-3}(4+2+32-1)=78\\amp;#10;2^{2x-3}*37=78\\amp;#10;2^{2x} = \frac{78*8}{37} = \frac{624}{37} \\amp;#10;2^x = \sqrt{ \frac{624}{37}} \\amp;#10;x = log_2\sqrt{ \frac{624}{37}}$

11.
$5^{1+x^2}-5^{1-x^2}=24|*5^{x^2}\\ 5*5^{2x^2}-5=24*5^{x^2}\\amp;#10;5^{x^2} = t,t\ \textgreater \ 0\\amp;#10;5t^2-24t - 5=0\\amp;#10;D = 576+100 = 676\\amp;#10;t = \frac{24+26}{10} =5\\amp;#10;5^{x^2} = 5^1\\amp;#10;x^2=1\\amp;#10;x_1=-1\\amp;#10;x_2=1$

182