Baamevob
6 год назад
Помогите решить надо найти f'(x) = 0
ОТВЕТЫ
Мартемьян
Jun 30, 2019
F (x) = 4x^3 + 12x^2 - 16x
f (x) = 0 ==gt;
4x^3 + 12x^2 - 16x = 0 /:4
x^3 +3x^2 - 4x = 0
x (x^2 + 3x - 4 ) = 0
1) x = 0 ;
2) x^2 + 3x - 4 = 0
D = 9 + 4*4 = 9 + 16 = 25 = 5^2
x1 = ( - 3 + 5)/2 = 2/2 = 1;
x2 = ( - 3 - 5 )/2 = - 8/ 2 = - 4
Ответ
- 4; 0; 1
f (x) = 0 ==gt;
4x^3 + 12x^2 - 16x = 0 /:4
x^3 +3x^2 - 4x = 0
x (x^2 + 3x - 4 ) = 0
1) x = 0 ;
2) x^2 + 3x - 4 = 0
D = 9 + 4*4 = 9 + 16 = 25 = 5^2
x1 = ( - 3 + 5)/2 = 2/2 = 1;
x2 = ( - 3 - 5 )/2 = - 8/ 2 = - 4
Ответ
- 4; 0; 1
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