Глеб
6 год назад
Sin(-t)/tg(-t)-cos(-2п+t)
ОТВЕТЫ
Kievizom
Jun 30, 2019
Решение
Sin(-t)/tg(-t)-cos(-2π+t) = (- sint)/(-tgt) - cos(2π - t) =
= sint/[(sint/cost)] - cost = cost - cost = 0
Sin(-t)/tg(-t)-cos(-2π+t) = (- sint)/(-tgt) - cos(2π - t) =
= sint/[(sint/cost)] - cost = cost - cost = 0
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