$x^{2} - 3x + \sqrt{5-x} = \sqrt{5-x} +18$

Question

Алгебра

Nuajurus

6 год назад

$x^{2} - 3x + \sqrt{5-x} = \sqrt{5-x} +18$

ОТВЕТЫ

Didyuknap

Jun 28, 2019

$x^2-3x+ \sqrt{5-x} = \sqrt{5-x} +18\\amp;#10;5-x \geq 0\\amp;#10;x \leq 5\\amp;#10;x^2-3x+ \sqrt{5-x} - \sqrt{5-x} -18=0\\amp;#10;x^2-3x-18=0\\amp;#10;D=3^2+4*18=9+72=81\\amp;#10;x_{1,2}= \frac{3\pm9}{2} \\x_1=6\\amp;#10;x_2=-3\\amp;#10;Otvet: x=-3$

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