Пж даю много поинтов ​

1)x+a2+3a=0D=(a−1)2+4⋅(a2+3a)=a2−2a+1+4a2+12a=5a2+10a+1x1​=2−(a−1)−5a2+10a+1​​=21−a−5a2+10a+1​​x2​=2−(a−1)+5a2+10a+1​​=21−a+5a2+10a+1​​x1​+x2​=421−a−5a2+10a+1​​+21−a+5a2+10a+1​​=41−a−5a2+10a+1​+1−a+5a2+10a+1​=82−2a=8−2a=6a=−3​