Алгебра | 10-11 класс
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RitaAc
4 год назад
√2cos(α - π/4) - sinα + cosα
cos(4 + α)sin(a - 41) - cos(α - 41)sin(α + 4)
(tg(π/8 + α) + tg(π/8 - α))/(1-tg(π/8 + α)tg(π/8 - α))
cosα = -0,6; π<α<3π/2
cos²α + cos²(61 + α) + cos²(60 - α)
2cos²(135 - 2,5α) - 1
(1 - tg²π/6)/(4tgπ/6)
tgα/8 = 3, tgβ/2 = -5
√(0,5 - 0,5cos4α), π/4 < α < π/2
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ОТВЕТЫ
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Snob
НЕ ЭКСПЕРТ
Ответил 2021-04-01 13:09:22
1. 2cosα
2. -√2/2
3. 1
СПАСИБО
0
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