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Neubvinam
4 год назад
Срочно
ОТВЕТЫ
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Radoslav
Jan 17, 2021
√2*sin(П/12-3х)-1=0√2*sin(П/12-3х)=1√2*sin(3x-П/12)=-1Делим обе части на √2:sin(3x-П/12)=–1/√2sin(3x-П/12)=–√2/23х-П/12 = (-1)ⁿ * arcsin(–√2/2) 2Пn; n∈Z3x-П/12 = (-1)^(n 1) * arcsin(√2/2) 2Пn; n∈Z3x-П/12 = (-1)^(n 1) * П/4 2Пn; n∈Z3x = (-1)^(n 1) * П/4 П/12 2Пn; n∈Zx = (-1)^(n 1) * П/12 П/36 (2/3)Пn; n∈Z
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