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Question

Алгебра

Gholbizel

4 год назад

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ОТВЕТЫ

Кондратий

Nov 29, 2020

$\frac{1}{3}\sqrt{423}=\sqrt{(\frac{1}{3})^{2}*423} =\sqrt{\frac{1}{9}*423}=\sqrt{47} \\\\\frac{1}{5}\sqrt{1150}=\sqrt{(\frac{1}{5})^{2}*1150}=\sqrt{\frac{1}{25}*1150}=\sqrt{46}\\\\47>46\Rightarrow\sqrt{47}>\sqrt{46}\Rightarrow\boxed{\frac{1}{3}\sqrt{423}>\frac{1}{5}\sqrt{1150}}$

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