посчитайте решить.. Очень ..

Question

Математика

Mokegrivv

6 год назад

посчитайте решить.. Очень ..

ОТВЕТЫ

Цветанка

Nov 27, 2020

$1)y' = 12 {x}^{5}- 32 {x}^{3}+ 12 {x}^{2}+ 4x$

$2)y' =\frac{5}{x}+ 4 \sin(x)- 1$

$3)y' = 9 \sin(x)+ (9x + 6) \cos(x)$

$4)y' =\frac{(4 +{e}^{x})( {x}^{2}- 3x - 1) - (2x - 3)(4x +{e}^{x})}{ {( {x}^{2} - 3x - 1) }^{2} }=\frac{4 {x}^{2} - 12x - 4 +{x}^{2}{e}^{x}- 3x {e}^{x} -{e}^{x}- 8 {x}^{2} - 2x {e}^{x}+ 12x + 3 {e}^{x}}{ {( {x}^{2} - 3x - 1) }^{2} }=\frac{ - 4 {x}^{2} +{x}^{2} {e}^{x}- 5x {e}^{x}- 4 + 2{e}^{x}}{ {( {x}^{2}- 3x - 1) }^{2} }=\frac{ {e}^{x}( {x}^{2}- 5x + 2) - 4(1 +{x}^{2} )}{ {( {x}^{2} - 3x - 1) }^{2} }$

$5)y' =\cos(1 - 6x)\times ( - 6) =- 6 \cos(1 - 6x)$

$6)y' = 2x {e}^{ {x}^{2}+ 2}$

$7)y' =\frac{5x}{x - 7}+ 5 ln(x - 7)+ 36 \sin(9x)$

$8)y' = 3 {x}^{2}log_{2}( {x}^{3} + x )+{x}^{3}\times\frac{1}{ ln(2)\times ( {x}^{3} + x) }\times (3 {x}^{2}+ 1) = 3 {x}^{2}log_{2}( {x}^{3}+ x)+\frac{ {x}^{3}(3 {x}^{2}+ 1) }{ ln(2)\times x( {x}^{2}+ 1)}= 3 {x}^{2}log_{2}( {x}^{3}+ x) +\frac{ {x}^{2}(3 {x}^{2}+ 1) }{( {x}^{2}+ 1) ln(2) }$

$9)y' =\frac{5 \cos(x - 4) + (7 + 5x) \sin(x - 4)}{ { \cos(x - 4) }^{2} }$

$10)y' = 5 {(2x + 1)}^{4}\times 2 \times{(x + 4)}^{9}+ 9 {(x + 4)}^{8}{(2x + 1)}^{5}={(2x + 1)}^{4}{(x + 4)}^{8} (10(x + 4) + 9(2x + 1)) ={(2x + 1)}^{4}{(x + 4)}^{8}(10x + 40 + 18x + 9) ={(2x + 1)}^{4}{(x + 4)}^{8}(28x + 49)$

$11)y' =\frac{- ln(2) \times{2}^{ - x}(5x +ln(3x + 8)) - (5 +\frac{3}{3x + 8}) {2}^{ - x}}{ {(5x +ln(3x + 8)) }^{2} }=\frac{ {2}^{ - x} ( -ln(2)(5x +ln(3x + 8) - (5 +\frac{3}{3x + 8} ))}{ {(5x +ln(3x + 8)) }^{2} }$

593