посчитайте решить

f(x)=-6x²+2x-3

f(2)=-6×2²+2×2-3=-23

f(0)=-3

f(-2)=-6×(-2)²-2×2-3=-31

f(2)×(4f(0)+3f(-2))=-23×(4×(-3)+3×(-31))=

=-23×(-12-93)=-105×(-23)=2415