посчитайте 9х-27/3x2-x3 + (3x+9/x-3)2 * (1/3x-9 + 2/9-x2 - 1/x2+3x) = 3(x2+9/x2(x-3)

( (1/27) *9^x) ^(2x +3 ) =(1/3)^ 9x ;

(3⁻³ *3²ˣ)^ (2x+3) = (3⁻¹)⁹ˣ ;

(3 ^(2x-3) ) ^(2x+3) =3⁻⁹ˣ ;

3^ ( 2x-3)(2x+3) ) = 3⁻⁹ˣ ;

(2x-3)(2x+3) = -9x ;

4x² - 9 = 9x ;

4x² -9x -9 =0 ;  D = 9² -4*4*(-9) =9(9+16) =9*25 =(3*5)² .

x₁= (9 -15)/2*4  = -3/4 ;

x ₂ =(9+15)/8 = 3 .

: -3/4 , 3.