5x-10/2x+3÷x²-4/4x+6

Question

Алгебра

Thorgawield

5 год назад

5x-10/2x+3÷x²-4/4x+6

ОТВЕТЫ

Hristina

Nov 16, 2020

$\frac{5 {x}^{3}+ 6 {x}^{2} - 6x + 3 }{ {x}^{2} }$

$5x -\frac{10}{2x}+ 3 \div{x}^{2}-\frac{4}{4x}+ 6 \\ 5x -\frac{5}{x}+\frac{3}{ {x}^{2} }-\frac{1}{x}+ 6 \\\frac{ {5x}^{3} - 5x + 3 - x +{6x}^{2}}{ {x}^{2} }\\\frac{ {5x}^{3} - 6x + 3 +{6x}^{2}}{ {x}^{2} }\\\frac{ {5x}^{3} +{6x}^{2} - 6x + 3}{ {x}^{2} }$

444

5x-10/2x+3÷x²-4/4x+6​

5x-10/2x+3÷x²-4/4x+6