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y'=2-2·cos(2·x)        y'=15·sin(x)-3·sin(3·x)

1)(2·x-sin(2·x))' = (-sin(2·x))' + (2·x)' = (-2·cos(2·x)) + 2 = 2-2·cos(2·x)

(-sin(2·x))' = (-sin(2·x))'(2·x)' = -2·cos(2·x)

(2·x)' = 2

2)(-15·cos(x)+cos(3·x)+8)' = (-15·cos(x))' + (cos(3·x))' + (8)' = 15·sin(x) + (-3·sin(3·x)) = 15·sin(x)-3·sin(3·x)

(cos(3·x))' = (cos(3·x))'(3·x)' = -3·sin(3·x)

(3·x)' = 3