ДАЮ 30 поинтов КТО СДЕЛАЕТ

Question

Алгебра

Lajurus

6 год назад

ДАЮ 30 поинтов КТО СДЕЛАЕТ

ОТВЕТЫ

Александра

Nov 14, 2020

1) $1.5 \times{2}^{4}-{3}^{2}=\frac{3}{2}\times 16 - 9 =\\ 3 \times 8 - 9 = 24 - 9 \\ 15$

${a}^{7}\times{a}^{4}={a}^{7 + 4}={a}^{11 }\\{a}^{7}\div{a}^{4}={a}^{7 - 4}={a}^{3}\\ ( {a}^{7} ) ^{4}={a}^{28}\\\frac{ {a}^{17} \times{ ({a}^{3}) }^{3}}{ {a}^{20} }=\frac{ {a}^{17}\times{a}^{9} }{ {a}^{20} }=\frac{ {a}^{17 + 9} }{ {a}^{20} }=\frac{ {a}^{26} }{ {a}^{20} }={a}^{6}$

$- 3 {x}^{3}{y}^{4}{x}^{5}\times 4 {y}^{3}=- 12 {x}^{9}{y}^{7}\\{( - 4 {a}^{6}b) }^{3}=- 64 {a}^{18}{b}^{3}$

$(5 {a}^{2}- 2a - 3) - (2 {a}^{2}+ 2a - 5) = 5 {a}^{2}- 2a - 3 - 2 {a}^{2}- 2a + 5 = 3 {a}^{2}- 4a + 2$

$\frac{ {49}^{5}\times{7}^{12} }{ {343}^{7} }=\frac{ {( {7}^{2}) }^{5} \times{7}^{12}}{ {( {7}^{3}) }^{7} }=\frac{ {7}^{10 + 12}}{ {7}^{21} }=\frac{ {7}^{22} }{ {7}^{21} }= 7$

${ (\frac{4}{7}) }^{6}\times{(1 \frac{3}{4} )}^{4}=\frac{ {4}^{6} }{ {7}^{6} }\times\frac{ {7}^{4} }{ {4}^{4} }=\frac{ {4}^{2} }{ {7}^{2} }$

$81 {x}^{5} y \times ( -\frac{1}{3} x {y}^{2} ) ^{3}= 81 {x}^{5} y \times ( -\frac{1}{27} ) {x}^{3}{y}^{6}=- 3 {x}^{8}{y}^{7}$

$(5 {x}^{2}- 3xy -{y}^{2} ) - (4 {x}^{2}- 6xy -{y}^{2} ) = 5 {x}^{2}- 3xy -{y}^{2}- 4 {x}^{2} + 6xy +{y}^{2}= {x}^{2}+ 3xy$

$- 8 {a}^{3} b =- 2 \times 4 {a}^{3} b =- 2 \times- 5 = 10 \\ 4 {a}^{6}{b}^{2}={a}^{3} b \times 4 {a}^{3} b ={a}^{3} b \times ( - 5) =- 5 {a}^{3} b$

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