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Question

Игнатий

6 год назад

ОТВЕТЫ

Стойко

Nov 14, 2020

$( \sqrt{20}-\sqrt{5} ) \times\sqrt{5}= (2 \sqrt{5}-\sqrt{5} ) \sqrt{5}=\sqrt{5}\sqrt{5}= 5$

$( \sqrt{18}-\sqrt{2} ) \times\sqrt{2}= (3 \sqrt{2}-\sqrt{2} ) \sqrt{2}= 2 \sqrt{2}\sqrt{2}= 2 \times 2 = 4$

$( \sqrt{48}-\sqrt{3} ) \times\sqrt{3}= ((4 \sqrt{3}-\sqrt{3} ) \sqrt{3}= 3 \sqrt{3}\sqrt{3}= 3 \times 3 = 9$

$( \sqrt{50}+\sqrt{2} ) \times\sqrt{2}= (5 \sqrt{2}+\sqrt{2} ) \sqrt{2}= 6 \sqrt{2}\sqrt{2}= 6 \times 2 = 12$

$( \sqrt{45}+\sqrt{5} ) \times\sqrt{5}= (3 \sqrt{5}+\sqrt{5} ) \sqrt{5}= 4 \sqrt{5}\sqrt{5}= 4 \times 5 = 20$

$( \sqrt{27}+\sqrt{3} ) \times\sqrt{3}= (3 \sqrt{3}+\sqrt{3} ) \sqrt{3}= 4 \sqrt{3}\sqrt{3}= 4 \times 3 = 12$

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