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Question

Савел

6 год назад

ОТВЕТЫ

Hodges Ronald

Nov 13, 2020

$-\frac{14 {c}^{12} }{ {a}^{6} {b}^{11}}\times\frac{ {a}^{5}{b}^{9} }{52 {c}^{7} }=-\frac{ 7{c}^{5} }{26a {b}^{2} }$

$\frac{7a - 7b}{2 {c}^{4} }\times\frac{6c}{ {a}^{2}-{b}^{2} }=\frac{7(a - b)}{2 {c}^{4} }\times\frac{6c}{(a - b)(a + b)}=\frac{21}{ {c}^{3} (a + b)}$

$\frac{84 {z}^{9} {y}^{6}}{ {x}^{11} }\times\frac{1}{48x {y}^{14} {z}^{7}}=\frac{7{z}^{2}}{4 {x}^{12}{y}^{8} }$

528