Log4(9)+2log4(8)-2log4(3)

Question

Алгебра

Аврелий

6 год назад

Log4(9)+2log4(8)-2log4(3)

ОТВЕТЫ

Лиляна

Nov 11, 2020

$log_{4}(9)+ 2 log_{4}(8)- 2 log_{4}(3)=log_{4}(9)+log_{4}( {8}^{2} )-log_{4}( {3}^{2} )=log_{4}( \frac{9 \times{8}^{2} }{ {3}^{2} } )=log_{4}( {8}^{2} )= log_{ {2}^{2} }(( {2}^{3} ) {}^{2} )=\frac{1}{2}log_{2}( {2}^{6} )=\frac{6}{2}log_{2}(2)= 3$

: 3

696

Log4(9)+2log4(8)-2log4(3)​

Log4(9)+2log4(8)-2log4(3)