50/4 + 3/7y = y/2 - 281/28(34 +х) -83 =4235/3x - 31/6 = 15/4 + 11/4

Question

Алгебра

Liakvach

6 год назад

50/4 + 3/7y = y/2 - 281/28(34 +х) -83 =4235/3x - 31/6 = 15/4 + 11/4

ОТВЕТЫ

Недялка

Nov 11, 2020

$\frac{50}{4}+\frac{3}{7}y=\frac{y}{2}-\frac{281}{28} \;\;|*28\\\\350+12y=14y-281\\\\-2y=-631\\\\y=315.5\\\\\\(34+x)-83=42\\\\34+x-83=42\\\\x=91\\\\\\\frac{35}{3}x-\frac{31}{6}=\frac{15}{4}+\frac{11}{4}\;\;|*12\\\\140x-62=78\\\\140x=140\\\\x=1$

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