((1∨1)∧(1∧0)= ((1∧1)∨0)∧(0∨1) =

A) (1 ∨ 1) ∧ (1 ∨ 0) = 1 ∧ 1 = 1;

B) (0 ∨ 1) ∨ (1 ∨ 0) = 1 ∨ 1 = 1;

Г) (1 ∧ 1) ∨ (1 ∧ 0) = 1 ∨ 0 = 1;