
Gavi
6 год назад
Продифференцировать функцию3х^2-6х+6х+12х^2х^3+6х
ОТВЕТЫ

Борис
Nov 9, 2020
(3х^2-6х+6)' = (3x^2)' - (6x)' + 6' = 6x + 6
(х+12х^2)' = x' + (12x^2)' = 1 + 24x
(х^3+6х)' = (x^3)' + (6x)' = 3x^2 + 6
149


(3х^2-6х+6)' = (3x^2)' - (6x)' + 6' = 6x + 6
(х+12х^2)' = x' + (12x^2)' = 1 + 24x
(х^3+6х)' = (x^3)' + (6x)' = 3x^2 + 6