A) (2x + 1)(10x - 7)>=0;

Question

Мартемьян

6 год назад

ОТВЕТЫ

Horton Peter

Nov 7, 2020

$(2x+1)*(10x-7)\geq 0$

$\left \{ {{2x+1\geq 0} \atop {10x-7\geq 0}} \right.$

$\left \{ {{2x+1\leq 0} \atop {10x-7\leq 0}} \right.$

$\left \{ {{x\geq -\frac{1}{2} } \atop {x\geq \frac{7}{10} }} \right.$

$\left \{ {{x\leq -\frac{1}{2} } \atop {x\leq \frac{7}{10} }} \right.$

x ∈ ( -∞ , - $\frac{1}{2}$ ] ∪ [ $\frac{7}{10}$ , + ∞ )

843

A) (2x + 1)(10x - 7)>=0;​