Arinius
5 год назад
Найти сумму всех целых двоичных чисел 10+100+110+1000+1010+...+10010. Ответ записать в шестнадцатеричнлй системе счисления.
ОТВЕТЫ
Мира
Oct 24, 2020
10_2 = 2_{10} \
100_2 = 4_{10} \
110_2 = 6_{10} \
... \
10010_2 = 18_{10} \
\
2+4+6+8+10+12+14+16+18=90 \
90_{10} = 80 + 10 = 5 times 16^1 + 10 times 16^0 = 5A \
\
5A
" title="
10_2 = 2_{10} \
100_2 = 4_{10} \
110_2 = 6_{10} \
... \
10010_2 = 18_{10} \
\
2+4+6+8+10+12+14+16+18=90 \
90_{10} = 80 + 10 = 5 times 16^1 + 10 times 16^0 = 5A \
\
5A
" alt="
10_2 = 2_{10} \
100_2 = 4_{10} \
110_2 = 6_{10} \
... \
10010_2 = 18_{10} \
\
2+4+6+8+10+12+14+16+18=90 \
90_{10} = 80 + 10 = 5 times 16^1 + 10 times 16^0 = 5A \
\
5A
" />
100_2 = 4_{10} \
110_2 = 6_{10} \
... \
10010_2 = 18_{10} \
\
2+4+6+8+10+12+14+16+18=90 \
90_{10} = 80 + 10 = 5 times 16^1 + 10 times 16^0 = 5A \
\
5A
" title="
10_2 = 2_{10} \
100_2 = 4_{10} \
110_2 = 6_{10} \
... \
10010_2 = 18_{10} \
\
2+4+6+8+10+12+14+16+18=90 \
90_{10} = 80 + 10 = 5 times 16^1 + 10 times 16^0 = 5A \
\
5A
" alt="
10_2 = 2_{10} \
100_2 = 4_{10} \
110_2 = 6_{10} \
... \
10010_2 = 18_{10} \
\
2+4+6+8+10+12+14+16+18=90 \
90_{10} = 80 + 10 = 5 times 16^1 + 10 times 16^0 = 5A \
\
5A
" />
425
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