125-b3 = 27a6+b9 = (a2+4b)2 = (3a-2)2 = 4a2c2-9x6 = 5d6c4-8x9 = ​

1)(5-b)(25+5b+b2(квадрат)

2.(3a2+b3)(9a4-3a2b3+b6)

3.2a2 + 8b

4.6a-4

5.2(2a2c2-27)

6.5c4d6 - 72