Евтихий
4 год назад
14x|x+2|+|x-2| x = -4 плиз фаст
ОТВЕТЫ
Евстигней
Oct 6, 2020
begin{gathered}ODZ:xgeq0\\40-14x+x^{2} =2(x-4)sqrt{x} \\x^{2} -14x+40=2sqrt{x}(x-4)\\(x-4)(x-10)-2sqrt{x}(x-4)=0\\(x-4)(x-10-2sqrt{x})=0\\[begin{array}{ccc}x-4=0\x-10-2sqrt{x} =0end{array}\\1)x-4=0Rightarrow x_{1}=4\\2)x-10-2sqrt{x}=0\\sqrt{x}=m,mgeq0\\m^{2} -2m-10=0\\D=(-2)^{2}-4*(-10)=4+40=44=(2sqrt{11})^{2}\\m_{1}=frac{2+2sqrt{11}}{2}=1+sqrt{11}\\m_{2}=frac{2-2sqrt{11}}{2}=1-sqrt{11} < 0-neydend{gathered}
begin{gathered}sqrt{x}=1+sqrt{11}\\x_{2} =(1+sqrt{11})^{2}\\x_{2} =1+2sqrt{11}+11=12+2sqrt{11}\\Otvet:boxed{4;12+2sqrt{11}}end{gathered}x=1+11x2=(1+11)2x2=1+211+11=12+211Otvet:4;12+211
400
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