{20х+40< = 0 {2/9-4/27х>0

Question

Математика

Gtg

5 год назад

{20х+40< = 0 {2/9-4/27х>0

ОТВЕТЫ

Olga

Oct 5, 2020

$left { {{20x+40leq 0} atop {frac{2}{9} -frac{4}{27}x >0}} right. \left { {{20xleq-40 } atop {-frac{4}{27}x>-frac{2}{9}}} right.\left { {{xleq-2 } atop {x<frac{2*27}{9*4} }} right.\left { {{xleq-2 } atop {x<frac{3}{2} }}$

⇒х∈(-∞;-2]

443

{20х+40< = 0 {2/9-4/27х>0​

{20х+40< = 0 {2/9-4/27х>0