(х^2+х) ^2-6(х^2+х) +8 = 0

Question

Высоцкий

4 год назад

ОТВЕТЫ

Galina

Oct 5, 2020

$bf (x^2+x) ^2-6(x^2+x) +8=0$

$t {}^{2}- 6t + 8 = 0$

$fbox{ t = 2 \ t = 4}$

$fbox{x {}^{2}+ x = 2 \ x {}^{2}+ x = 4}$

$fbox{x =- 2 \ x = 1 \ x =dfrac{ - 1 +sqrt{17} }{2}\ x =dfrac{ - 1 -sqrt{17} }{2} }$

$fbox{x_{1} =- 2 \ x_{2} = 1 \ x_{3} =dfrac{ - 1 +sqrt{17} }{2}\ x_{4} =dfrac{ - 1 -sqrt{17} }{2} }$

72

(х^2+х) ^2-6(х^2+х) +8 = 0​