Huhuginn
7 год назад
(tg^2 x) / (1 - tg^2 x) = 1/2? Найти Х
ОТВЕТЫ
Arefiy
Aug 15, 2019
Tg²x/(1-tg²x)=1/2
t=tg²x, t²/(1-t²)=1/2, 2t²=1-t², 3t²=1, t²=1/3, t₁=1/√3, t₂=-1/√3
tgx=1/√3 tgx=-1/√3
x=π/6+πn, n∈Z x=-π/6+πn, n∈Z
t=tg²x, t²/(1-t²)=1/2, 2t²=1-t², 3t²=1, t²=1/3, t₁=1/√3, t₂=-1/√3
tgx=1/√3 tgx=-1/√3
x=π/6+πn, n∈Z x=-π/6+πn, n∈Z
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